LINEAR LAW in Pure Mathematics 2 (AS Level CAMBRIDGE PAST PAPER)
LINEAR LAW in Pure Mathematics 2 (AS Level)
Question:
Answer:
%7D "y=Ae^{p(x-1)}")
%7D "y/A=e^{p(x-1)}")
=ln&space;e%5E%7Bp(x-1)%7D "ln (y/A)=ln e^{p(x-1)}")
-ln(A)&space;&space;p(x-1) "ln(y)-ln(A) = p(x-1)")
&space;ln(A)&space;+&space;p(x-1) "ln(y)= ln(A) + p(x-1)")
&space;&space;ln&space;(A)+&space;px&space;-&space;p "ln (y) = ln (A)+ px - p")
&space;&space;%5Bln&space;(A)&space;-&space;p&space;%5D+&space;px "ln (y) = [ln (A) - p ]+ px")
Based on graph:
m = (2.92-1.60)/(5-2)
= 0.44
So m = p = 0.44
Question:
[Taken from Paper 2 Pure Mathematics 2 (P2) Cambridge International Examinations Advanced Subsidiary Level, May/June 2015]
Answer:
Based on graph:
m = (2.92-1.60)/(5-2)
= 0.44
So m = p = 0.44
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